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On a 3d board, would this piece also be able to make a 5:4:3 leap? After all, the length of that is quite obviously root 50 as well. Even with that leap the piece would of course still be colourbound, and the board would need one dimension of at least 8 and another of at least 6 to give the piece all its moves.
Hmm...the Root-fifty leaper currently seems to be the only piece of its kind...interesting concept...
Christine Bagley-Jones has provided a ZRF for her new variant SKY, which uses both the Root-fifty leaper and the Root-twenty-five leaper [a (0,5) and (4,3) leaper]. She calls the latter a 'Fiveleaper' - but I believe that term should be reserved for a pure (0,5) leaper.
well i called the 0-5, 4-3 leaper a fiveleaper, because i've never seen it referred to as anything else. if you 'google' the word 'fiveleaper' plenty of websites have info on the fiveleaper, and every single one i've seen gives the fiveleaper as a 0-5, 4-3 leaper. some sites are pretty cool too, here is an amazing one that gives 'fiveleaper tours' on a 8x8 board, see how many there are! http://www.ktn.freeuk.com/9f.htm
The piece which moves (4,3) or (5,0) is definitely called a '5-leaper' in the Oxford Companion to Chess.
On another note, there's a misprint on this page: 'one square diagonally' should read 'one square horizontally'.
I did not understand: why it's square root of 50?
Edited because I had miread your question as 'What is the square root of fifty?' and answered that. It is the square root of 50 because the sum of the squares of the two shorter sides of a right-angled triangle equals the square of the longer sides. The squares of the 5s are both 25, summing to 50, and the squares of 7 and 1 are 49 and 1, also summing to 50.
It's also color-bound.
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