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Knightmate. Win by mating the knight. (8x8, Cells: 64) [All Comments] [Add Comment or Rating]
Peter Aronson wrote on Tue, Aug 13, 2002 05:10 PM UTC:

What about this situation (white to move):

   +---+---+---+---+---+---+---+---+
8  |   |:::|   |:::|   |:::|   |:::|
   +---+---+---+---+---+---+---+---+
7  |:::| P |:::|   |:::|   |:::|   |
   +---+---+---+---+---+---+---+---+
6  |   |:::|   |:::|   |:::|   |:::|
   +---+---+---+---+---+---+---+---+
5  |:::|   |:::|   |:::|   |:::|   |
   +---+---+---+---+---+---+---+---+
4  |   |:::|   |:::|   |:::|   |:::|
   +---+---+---+---+---+---+---+---+
3  |:::|   |:::|   |:::|   |:::|   |
   +---+---+---+---+---+---+---+---+
2  |   |:::|   |:::|   |:::|   |:::|
   +---+---+---+---+---+---+---+---+
1  |:n:|   |:::|   |:N:|   |:::|   |
   +---+---+---+---+---+---+---+---+
     a   b   c   d   e   f   g   h

If white b8=Q or b8=R, then stalemate. If b8=B, then I believe there is insufficient material for mate -- thus b8=K. I'm fairly sure that K+N can mate bare N. If not, add a B at g1. Two B on the same color + N vs N is still not promising, but K+B+N vs N is surely enough!