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The birth of two variants: Apothecary chess 1 & Apothecary chess 2[Subject Thread] [Add Response]
H. G. Muller wrote on Wed, Sep 28, 2016 02:02 PM UTC:

You mean in the expression for the statistical error? In the absence of draws it would have been 50%, because in a single game you would always be 0.5 point away from the average, which is 50% of the total score. With draws this gets a bit lower, because you can also be exactly on the average. But for equal wins / losses / drawsit is still about 40%. Here you have less draws than wins or losses, so I just guessed a value somewhere in between, without calculating. It doesn't really matter much whether it would be 43% or 47%...