In continuation legs z and q have the meaning 'opposit' or 'same' as the previous l or r (possibly implied by z or q). The problem here, however, is that the first 4-fold symmetry breaking is different for the left and right bending paths. For the Ship, which had a similar problem, I got around that by arbitrarily assigning the four Ferz moves an l or an r (alternating as you go around the clock), even though. But here you start with a W move.
I suppose I could also make an assignment for orthogonal atoms, where the sideway moves have opposit helicity. (Currently all moves appear to have the same; afzW gives you a chiral Mao.) Then you could have written [sW?fzF?fqR]. The question is what to do for the vertical moves. Perhaps both z and q should be interpreted as s there.
I don't see any difference between bracket and other notation w.r.t z and q. There shouldn't be, as the preprocessor first converts bracket notation to the other.
In continuation legs z and q have the meaning 'opposit' or 'same' as the previous l or r (possibly implied by z or q). The problem here, however, is that the first 4-fold symmetry breaking is different for the left and right bending paths. For the Ship, which had a similar problem, I got around that by arbitrarily assigning the four Ferz moves an l or an r (alternating as you go around the clock), even though. But here you start with a W move.
I suppose I could also make an assignment for orthogonal atoms, where the sideway moves have opposit helicity. (Currently all moves appear to have the same; afzW gives you a chiral Mao.) Then you could have written [sW?fzF?fqR]. The question is what to do for the vertical moves. Perhaps both z and q should be interpreted as s there.
I don't see any difference between bracket and other notation w.r.t z and q. There shouldn't be, as the preprocessor first converts bracket notation to the other.