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Wildebeest Chess. Variant on an 10 by 11 board with extra jumping pieces. (11x10, Cells: 110) (Recognized!)[All Comments] [Add Comment or Rating]

Mark Thompson wrote on Mon, Oct 25, 2004 07:57 PM UTC:Good ★★★★

The basic idea of the game is that, as there are two simple sliders (B, R)
and one combination slider (B+R=Q), so in Wildebeest Chess there are also
two simple jumpers (Knight = (1,2) jumper and Camel = (1,3) jumper), and
one combined jumper (Wildebeest = N+C). I wonder how well the idea would
work instead with Knights and Zebras ((2,3) jumpers), and a combination
N+Z piece?

There is the idea that, as one of the sliders is color-bound, so perhaps
one of the jumpers ought to be also, hence the Camel. But it's not
obvious to me that rule makes for the best game. I'd be interesting in
knowing whether Wayne Schmittberger or anyone else has tried it. 

Actually, since the preset to enforce the rules has not been written for
this game yet, it would be possible to try playing this way, simply
entering Zebra moves for Camels and Knight/Zebra moves for the Wildebeest.