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I would think this is impossible. Diagonal moves of a certain length L have always lower average mobility than orthogonal moves of the same length: (S-L)*(S-L)/(S*S) instead of (S-L)/S, where S is the board size. They would get the same reduction factor because of board population, so blocking of moves doesn't alter that, no matter how you calculate it.
Yes, I rethought it and it's probably a programming error!...
@HG
Bug found!
I was adding a bishop ray twice!... Shame on me for not noticing!...
I guess this is how people sometimes find "faster than light" objects.
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I have written a small c++ program that calculates the crowded board mobility (betza style : https://www.chessvariants.com/d.betza/pieceval/betterway.html).
For a future variant I have studied what I'd prefer for now to call 2-picket bishop and 2-picket rook. Meaning a bishop that moves at least three squares (has 2 long mandatory blind slides before) and a rook that does the same.
It seems that the 2-picket bishop is slightly stronger than a than a 2-picket rook 12x12 and I think I figured out why, but first I'm curious on other opinions. The results averaged over the board having between 10 and 84 pieces (so 75 different cases) are
2pb mobility: 4.52381
2pr mobility: 4.22735
Sure there is still the issue of colour boundness but for compund pieces it is quite an interesting observation, I think!...